Advertisements
Advertisements
Question
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 2000, Rate = 4 paise per rupee per annum, Time = 3 years
Advertisements
Solution
\[\text{ Applying the rule A = P }\left( 1 + \frac{R}{100} \right)^n \text{ on the given situations, we get: }\]
\[A = 2, 000 \left( 1 + \frac{4}{100} \right)^3 \]
\[ = 2, 000 \left( 1 . 04 \right)^3 \]
= Rs 2, 249 . 68
Now,
CI = A - P
= Rs 2, 249 . 68 - Rs 2, 000
= Rs 249 . 68
RELATED QUESTIONS
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 5%, Time = 2 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 12800, Rate = \[7\frac{1}{2} %\], Time = 3 years
The difference between the compound interest and simple interest on a certain sum at 15% per annum for 3 years is Rs 283.50. Find the sum.
At what rate percent will a sum of Rs 1000 amount to Rs 1102.50 in 2 years at compound interest?
The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.
The population of a town increases at the rate of 40 per thousand annually. If the present population be 175760, what was the population three years ago.
The production of a mixi company in 1996 was 8000 mixies. Due to increase in demand it increases its production by 15% in the next two years and after two years its demand decreases by 5%. What will be its production after 3 years?
The value of a machine depreciates at the rate of 10% per annum. What will be its value 2 years hence, if the present value is Rs 100000? Also, find the total depreciation during this period.
Mohan purchased a house for Rs 30000 and its value is depreciating at the rate of 25% per year. Find the value of the house after 3 years.
Find the difference between simple interest and compound interest on ₹ 20000 at 8 p.c.p.a.
