Advertisements
Advertisements
Question
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 2000, Rate = 4 paise per rupee per annum, Time = 3 years
Advertisements
Solution
\[\text{ Applying the rule A = P }\left( 1 + \frac{R}{100} \right)^n \text{ on the given situations, we get: }\]
\[A = 2, 000 \left( 1 + \frac{4}{100} \right)^3 \]
\[ = 2, 000 \left( 1 . 04 \right)^3 \]
= Rs 2, 249 . 68
Now,
CI = A - P
= Rs 2, 249 . 68 - Rs 2, 000
= Rs 249 . 68
APPEARS IN
RELATED QUESTIONS
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 160000, Rate = 10 paise per rupee per annum compounded half-yearly, Time = 2 years.
The population of a town increases at the rate of 40 per thousand annually. If the present population be 175760, what was the population three years ago.
The production of a mixi company in 1996 was 8000 mixies. Due to increase in demand it increases its production by 15% in the next two years and after two years its demand decreases by 5%. What will be its production after 3 years?
Jitendra set up a factory by investing Rs 2500000. During the first two successive years his profits were 5% and 10% respectively. If each year the profit was on previous year's capital, compute his total profit.
The value of a machine depreciates at the rate of 10% per annum. What will be its value 2 years hence, if the present value is Rs 100000? Also, find the total depreciation during this period.
Ashish started the business with an initial investment of Rs 500000. In the first year he incurred a loss of 4%. However during the second year he earned a profit of 5% which in third year rose to 10%. Calculate the net profit for the entire period of 3 years.
To start a business, Shalaka has taken a loan of ₹8000 at a rate of 10 `1/2` p.c.p.a. After two years, how much compound interest will she have to pay?
The cost price of a machine is 2,50,000. If the rate of depreciation is 10% per year, find the depreciation in price of the machine after two years.
The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.
The value of a car, bought for Rs 4,40,000 depreciates each year by 10% of its value at the beginning of that year. So its value becomes Rs 3,08,000 after three years.
