Advertisements
Advertisements
Question
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 5000, Rate = 10 paise per rupee per annum, Time = 2 years
Advertisements
Solution
\[\text{ Applying the rule A = P }\left( 1 + \frac{R}{100} \right)^n \text{ on the given situations, we get: }\]
\[A = 5, 000 \left( 1 + \frac{10}{100} \right)^2 \]
\[ = 5, 000 \left( 1 . 10 \right)^2 \]
= Rs 6, 050
Now,
CI = A - P
= Rs 6, 050 - Rs 5, 000
= Rs 1, 050
APPEARS IN
RELATED QUESTIONS
A scooter was bought at Rs 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year.
Find the compound interest on Rs 160000 for one year at the rate of 20% per annum, if the interest is compounded quarterly.
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 18%, Time = 2 years
The compound interest on Rs 1800 at 10% per annum for a certain period of time is Rs 378. Find the time in years.
There is a continuous growth in population of a village at the rate of 5% per annum. If its present population is 9261, what it was 3 years ago?
The annual rate of growth in population of a certain city is 8%. If its present population is 196830, what it was 3 years ago?
Ms. Cherian purchased a boat for Rs 16000. If the total cost of the boat is depreciating at the rate of 5% per annum, calculate its value after 2 years.
The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.
The cost of a sewing machine is Rs 7,000. Its value depreciates at 8% p.a. Then the value of the machine after 2 years is Rs 5,924.80.
The population of a town was decreasing every year due to migration, poverty and unemployment. The present population of the town is 6,31,680. Last year the migration was 4% and the year before last, it was 6%. What was the population two years ago?
