Advertisements
Advertisements
Question
The cost price of a machine is 2,50,000. If the rate of depreciation is 10% per year, find the depreciation in price of the machine after two years.
Advertisements
Solution
Here, P = Cost price of the machine = 2,50,000
A = Cost price after 2 years
I = Depreciation in price after 2 years
R = Rate of depreciation = 10 %
N = 2 years
A = P `(1 + "R"/100)^"N"`
= 2,50,000 `(1 + (-10)/100)^2`
= 2,50,000 `(1 - 1/100)^2`
= 2,50,000 `((100 - 10)/100)^2`
= 2,50,000 `(90/100)^2`
= 2,50,000 `(9/10)^2`
= 2,50,000 `(81/100)`
= 2,500 × 81
= 2,02,500
Depreciation in price = Cost price (P) – Depreciated price (A)
= 2,50,000 − 2,02,500
= 47,500
∴ The depreciation in the price of the machine after 2 years would be 47,500.
RELATED QUESTIONS
The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would be its population in 2005?
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 5%, Time = 2 years
The difference between the compound interest and simple interest on a certain sum at 15% per annum for 3 years is Rs 283.50. Find the sum.
The compound interest on Rs 1800 at 10% per annum for a certain period of time is Rs 378. Find the time in years.
Aman started a factory with an initial investment of Rs 100000. In the first year, he incurred a loss of 5%. However, during the second year, he earned a profit of 10% which in the third year rose to 12%. Calculate his net profit for the entire period of three years.
Pritam bought a plot of land for Rs 640000. Its value is increasing by 5% of its previous value after every six months. What will be the value of the plot after 2 years?
Ashish started the business with an initial investment of Rs 500000. In the first year he incurred a loss of 4%. However during the second year he earned a profit of 5% which in third year rose to 10%. Calculate the net profit for the entire period of 3 years.
Find the compound interest if the amount of a certain principal after two years is ₹ 4036.80 at the rate of 16 p.c.p.a.
The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.
Find the amount and the compound interest on ₹ 10,000 in 3 years, if the rates of interest for the successive years are 10%, 15%, and 20% respectively.
