मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता ८ वी

The cost price of a machine is 2,50,000. If the rate of depreciation is 10% per year, find the depreciation in price of the machine after two years.

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प्रश्न

The cost price of a machine is 2,50,000. If the rate of depreciation is 10% per year, find the depreciation in price of the machine after two years.

बेरीज
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उत्तर

Here, P = Cost price of the machine = 2,50,000

A = Cost price after 2 years

I = Depreciation in price after 2 years

R = Rate of depreciation = 10 %

N = 2 years

A = P `(1 + "R"/100)^"N"`

= 2,50,000 `(1 + (-10)/100)^2`

= 2,50,000 `(1 - 1/100)^2`

= 2,50,000 `((100 - 10)/100)^2`

= 2,50,000 `(90/100)^2`

= 2,50,000 `(9/10)^2`

= 2,50,000 `(81/100)`

= 2,500 × 81

= 2,02,500

Depreciation in price = Cost price (P) – Depreciated price (A)

= 2,50,000 − 2,02,500

= 47,500

∴ The depreciation in the price of the machine after 2 years would be 47,500.

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पाठ 14: Compound interest - Practice Set 14.2 [पृष्ठ ९३]

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बालभारती Mathematics [English] Standard 8 Maharashtra State Board
पाठ 14 Compound interest
Practice Set 14.2 | Q 4 | पृष्ठ ९३
बालभारती Mathematics Integrated [English] Standard 8 Maharashtra State Board
पाठ 14 Compound Interest
Practice Set 14.2 | Q 4. | पृष्ठ ४८

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