Advertisements
Advertisements
प्रश्न
There is a continuous growth in population of a village at the rate of 5% per annum. If its present population is 9261, what it was 3 years ago?
Advertisements
उत्तर
Population after three years = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[9, 261 = P \left( 1 + \frac{5}{100} \right)^3 \]
\[9, 261 = P \left( 1 . 05 \right)^3 \]
\[P = \frac{9, 261}{1 . 157625}\]
\[ = 8, 000\]
Thus, the population three years ago was 8, 000.
संबंधित प्रश्न
The population of a place increased to 54000 in 2003 at a rate of 5% per annum Find the population in 2001.
The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would be its population in 2005?
The population of a city is 125000. If the annual birth rate and death rate are 5.5% and 3.5% respectively, calculate the population of city after 3 years.
The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.
Three years ago, the population of a town was 50000. If the annual increase during three successive years be at the rate of 4%, 5% and 3% respectively, find the present population.
In a factory the production of scooters rose to 46305 from 40000 in 3 years. Find the annual rate of growth of the production of scooters.
The population of a city increases each year by 4% of what it had been at the beginning of each year. If the population in 1999 had been 6760000, find the population of the city in (i) 2001 (ii) 1997.
Pritam bought a plot of land for Rs 640000. Its value is increasing by 5% of its previous value after every six months. What will be the value of the plot after 2 years?
The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If its present value is Rs 43740, find its purchase price.
A loan of ₹ 15000 was taken on compound interest. If the rate of compound interest is 12 p.c.p.a. find the amount to settle the loan after 3 years.
