Advertisements
Advertisements
प्रश्न
The population of a place increased to 54000 in 2003 at a rate of 5% per annum Find the population in 2001.
Advertisements
उत्तर
It is given that, population in the year 2003 = 54,000
Therefore,
54000 = (Population in 2001)`(1 + 5/100)^2`
= 54000
Population in 2001 = `54000 xx 20/21xx20/21`
= 48979.59
Thus, the population in the year 2001 was approximately 48,980.
संबंधित प्रश्न
In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.
Find the compound interest on Rs 160000 for one year at the rate of 20% per annum, if the interest is compounded quarterly.
The difference between the compound interest and simple interest on a certain sum at 15% per annum for 3 years is Rs 283.50. Find the sum.
The population of a town increases at the rate of 50 per thousand. Its population after 2 years will be 22050. Find its present population.
The value of a refrigerator which was purchased 2 years ago, depreciates at 12% per annum. If its present value is Rs 9680, for how much was it purchased?
In a forest there are 40,000 trees. Find the expected number of trees after 3 years if the objective is to increase the number at the rate 5% per year.
A loan of ₹ 15000 was taken on compound interest. If the rate of compound interest is 12 p.c.p.a. find the amount to settle the loan after 3 years.
Gautam takes a loan of ₹ 16,000 for 2 years at 15% p.a. compound interest. He repays ₹ 9,000 at the end of the first year. How much must he pay at the end of the second year to clear the debt?
The cost of a sewing machine is Rs 7,000. Its value depreciates at 8% p.a. Then the value of the machine after 2 years is Rs 5,924.80.
In the year 2001, the number of malaria patients admitted in the hospitals of a state was 4,375. Every year this number decreases by 8%. Find the number of patients in 2003.
