Advertisements
Advertisements
प्रश्न
The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would be its population in 2005?
Advertisements
उत्तर
Population in 2005 = 54000 `(1 + 5/100)`
= `54000 (1 + 1/20)^2`
= `54000 xx 21/20 xx 21/20`
= 59535
Thus, the population in 2005 would be 59,535.
APPEARS IN
संबंधित प्रश्न
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 18%, Time = 2 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 5000, Rate = 10 paise per rupee per annum, Time = 2 years
In a factory the production of scooters rose to 46305 from 40000 in 3 years. Find the annual rate of growth of the production of scooters.
The population of a city increases each year by 4% of what it had been at the beginning of each year. If the population in 1999 had been 6760000, find the population of the city in (i) 2001 (ii) 1997.
The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If its present value is Rs 43740, find its purchase price.
Sameerrao has taken a loan of ₹ 12500 at a rate of 12 p.c.p.a. for 3 years. If the interest is compounded annually, then how many rupees should he pay to clear his loan?
To start a business, Shalaka has taken a loan of ₹8000 at a rate of 10 `1/2` p.c.p.a. After two years, how much compound interest will she have to pay?
A loan of ₹ 15000 was taken on compound interest. If the rate of compound interest is 12 p.c.p.a. find the amount to settle the loan after 3 years.
Find the difference between simple interest and compound interest on ₹ 20000 at 8 p.c.p.a.
In the year 2001, the number of malaria patients admitted in the hospitals of a state was 4,375. Every year this number decreases by 8%. Find the number of patients in 2003.
