Advertisements
Advertisements
प्रश्न
The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would be its population in 2005?
Advertisements
उत्तर
Population in 2005 = 54000 `(1 + 5/100)`
= `54000 (1 + 1/20)^2`
= `54000 xx 21/20 xx 21/20`
= 59535
Thus, the population in 2005 would be 59,535.
APPEARS IN
संबंधित प्रश्न
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 5%, Time = 2 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 5000, Rate = 10 paise per rupee per annum, Time = 2 years
The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.
The count of bacteria in a culture grows by 10% in the first hour, decreases by 8% in the second hour and again increases by 12% in the third hour. If the count of bacteria in the sample is 13125000, what will be the count of bacteria after 3 hours?
The population of a city increases each year by 4% of what it had been at the beginning of each year. If the population in 1999 had been 6760000, find the population of the city in (i) 2001 (ii) 1997.
The cost of a T.V. set was quoted Rs 17000 at the beginning of 1999. In the beginning of 2000 the price was hiked by 5%. Because of decrease in demand the cost was reduced by 4% in the beginning of 2001. What was the cost of the T.V. set in 2001?
To start a business, Shalaka has taken a loan of ₹8000 at a rate of 10 `1/2` p.c.p.a. After two years, how much compound interest will she have to pay?
On the construction work of a flyover bridge there were 320 workers initially. The number of workers were increased by 25% every year. Find the number of workers after 2 years.
Find the amount and the compound interest on ₹ 10,000 in 3 years, if the rates of interest for the successive years are 10%, 15%, and 20% respectively.
In the year 2001, the number of malaria patients admitted in the hospitals of a state was 4,375. Every year this number decreases by 8%. Find the number of patients in 2003.
