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Maharashtra State BoardSSC (English Medium) 8th Standard

Sameerrao has taken a loan of ₹ 12500 at a rate of 12 p.c.p.a. for 3 years. If the interest is compounded annually, then how many rupees should he pay to clear his loan? - Mathematics

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Question

Sameerrao has taken a loan of ₹ 12500 at a rate of 12 p.c.p.a. for 3 years. If the interest is compounded annually, then how many rupees should he pay to clear his loan?

Sum
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Solution

Here, P = ₹ 12500; R = 12% ; N = 3 years

A = P `(1 + R/100)^N`

   = `12500 (1 + 12/100)^3`

   = `12500 ((100 + 12)/100)^3`

    = `12500 (112/100)^3`

    = `12500 ((28 xx 4)/(25 xx 4))^3`

    = `12500 (28/25)^3`

    = `12500 xx 28/25 xx 28/25 xx 28/25`

     = `20/25 xx 28 xx 28 xx 28`

     = `0.8 xx 28 xx 28 xx 28`

    = ₹ `17561.60`

Hence, he should pay an amount of  ₹ 17561.60 to clear his loan.

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Chapter 14: Compound interest - Practice Set 14.1 [Page 90]

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Balbharati Mathematics [English] Standard 8 Maharashtra State Board
Chapter 14 Compound interest
Practice Set 14.1 | Q 2 | Page 90
Balbharati Mathematics Integrated [English] Standard 8 Maharashtra State Board
Chapter 14 Compound Interest
Practice Set 14.1 | Q 2. | Page 45

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