Advertisements
Advertisements
Question
The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If its present value is Rs 43740, find its purchase price.
Advertisements
Solution
Purchase price = P \[\left( 1 - \frac{R}{100} \right)^{- n} \]
\[ \Rightarrow 43, 740 \left( 1 - \frac{10}{100} \right)^{- 3} \]
\[ = 43, 740 \left( 0 . 90 \right)^{- 3} \]
\[ = 60, 000\]
Thus, the purchase price of the machine was Rs 60, 000.
APPEARS IN
RELATED QUESTIONS
The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would be its population in 2005?
At what rate percent will a sum of Rs 1000 amount to Rs 1102.50 in 2 years at compound interest?
The annual rate of growth in population of a certain city is 8%. If its present population is 196830, what it was 3 years ago?
Ms. Cherian purchased a boat for Rs 16000. If the total cost of the boat is depreciating at the rate of 5% per annum, calculate its value after 2 years.
On the construction work of a flyover bridge there were 320 workers initially. The number of workers were increased by 25% every year. Find the number of workers after 2 years.
The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.
Gautam takes a loan of ₹ 16,000 for 2 years at 15% p.a. compound interest. He repays ₹ 9,000 at the end of the first year. How much must he pay at the end of the second year to clear the debt?
The population of a city was 20,000 in the year 1997. It increased at the rate of 5% p.a. Find the population at the end of the year 2000.
The value of a car, bought for Rs 4,40,000 depreciates each year by 10% of its value at the beginning of that year. So its value becomes Rs 3,08,000 after three years.
