Advertisements
Advertisements
Question
The cost of a T.V. set was quoted Rs 17000 at the beginning of 1999. In the beginning of 2000 the price was hiked by 5%. Because of decrease in demand the cost was reduced by 4% in the beginning of 2001. What was the cost of the T.V. set in 2001?
Advertisements
Solution
Cost of the TV = P \[\left( 1 + \frac{R}{100} \right)\left( 1 - \frac{R}{100} \right)\]
\[ \Rightarrow 17, 000\left( 1 + \frac{5}{100} \right)\left( 1 - \frac{4}{100} \right)\]
\[ = 17, 000\left( 1 . 05 \right)\left( 0 . 96 \right)\]
\[ = 17, 136\]
Thus, the cost the TV in 2001 was Rs 17, 136.
APPEARS IN
RELATED QUESTIONS
The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would be its population in 2005?
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 18%, Time = 2 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 5000, Rate = 10 paise per rupee per annum, Time = 2 years
There is a continuous growth in population of a village at the rate of 5% per annum. If its present population is 9261, what it was 3 years ago?
The annual rate of growth in population of a certain city is 8%. If its present population is 196830, what it was 3 years ago?
A loan of ₹ 15000 was taken on compound interest. If the rate of compound interest is 12 p.c.p.a. find the amount to settle the loan after 3 years.
A principal amounts to ₹ 13,924 in 2 years by compound interest at 18 p.c.p.a. Find the principal.
Gautam takes a loan of ₹ 16,000 for 2 years at 15% p.a. compound interest. He repays ₹ 9,000 at the end of the first year. How much must he pay at the end of the second year to clear the debt?
Find the amount and the compound interest on ₹ 10,000 in 3 years, if the rates of interest for the successive years are 10%, 15%, and 20% respectively.
In the year 2001, the number of malaria patients admitted in the hospitals of a state was 4,375. Every year this number decreases by 8%. Find the number of patients in 2003.
