Advertisements
Advertisements
Question
The value of (3x3 + 9x2 + 27x) ÷ 3x is ______.
Options
x2 + 9 + 27x
3x3 + 3x2 + 27x
3x3 + 9x2 + 9
x2 + 3x + 9
Advertisements
Solution
The value of (3x3 + 9x2 + 27x) ÷ 3x is x2 + 3x + 9.
Explanation:
We have,
`(3x^3 + 9x^2 + 27x) ÷ 3x = (3x^3 + 9x^2 + 27x)/(3x)`
= `(3x^3)/(3x) + (9x^2)/(3x) + (27x)/(3x)`
= x2 + 3x + 9
APPEARS IN
RELATED QUESTIONS
Constant is only 8 other is variable ax + 9
Subtract the second expression from the first:
a3 - 1 + a, 3a - 2a2
Simplify: (p – 2q) – (3q – r)
Simplify: (x + y – z)x + (z + x – y)y – (x + y – z)z
Find the numerical co-efficient of the following term:
−3yx
Factorise the following expression.
y2 + 8zx – 2xy – 4yz
Factorise the following expression.
a2b + a2c + ab + ac + b2c + c2b
Identify the term and its factor in the following expression.
Show the term and factor by tree diagram.
1 + x + x2
Identify the term and its factor in the following expression.
Show the term and factor by tree diagram.
y − y3
Identify term and factor in the expression given below:
`3/4 x + 1/4`
