Advertisements
Advertisements
Question
The value of (3x3 + 9x2 + 27x) ÷ 3x is ______.
Options
x2 + 9 + 27x
3x3 + 3x2 + 27x
3x3 + 9x2 + 9
x2 + 3x + 9
Advertisements
Solution
The value of (3x3 + 9x2 + 27x) ÷ 3x is x2 + 3x + 9.
Explanation:
We have,
`(3x^3 + 9x^2 + 27x) ÷ 3x = (3x^3 + 9x^2 + 27x)/(3x)`
= `(3x^3)/(3x) + (9x^2)/(3x) + (27x)/(3x)`
= x2 + 3x + 9
APPEARS IN
RELATED QUESTIONS
Identify the terms, their coefficients for the following expressions.
4x2y2 − 4x2y2z2 + z2
Identify the terms, their coefficients for the following expressions.
3 − pq + qr − rp
Write the degree of the following polynomial: 7 – 3x2y + y2
Add : 18pq – 15pq and 3pq
Find the sum of: 4a2 + 5b2 – 6ab, 3ab, 6a2 – 2b2 and 4b2 – 5 ab
Enclose the given term in bracket as required:
– 2a2 + 4ab – 6a2b2 + 8ab2 = – 2a (………)
Common factor of ax2 + bx is ______.
Write the greatest common factor in the following terms.
3x2y, 18xy2, – 6xy
Factorise the following expression.
2x2 – 2y + 4xy – x
Write the coefficient of x2 in the following:
y + y2x + y3x2 + y4x3
