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प्रश्न
The value of (3x3 + 9x2 + 27x) ÷ 3x is ______.
विकल्प
x2 + 9 + 27x
3x3 + 3x2 + 27x
3x3 + 9x2 + 9
x2 + 3x + 9
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उत्तर
The value of (3x3 + 9x2 + 27x) ÷ 3x is x2 + 3x + 9.
Explanation:
We have,
`(3x^3 + 9x^2 + 27x) ÷ 3x = (3x^3 + 9x^2 + 27x)/(3x)`
= `(3x^3)/(3x) + (9x^2)/(3x) + (27x)/(3x)`
= x2 + 3x + 9
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