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प्रश्न
Factorise the following expression.
x3y2 + x2y3 – xy4 + xy
योग
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उत्तर
We have,
x3y2 + x2y3 – xy4 + xy
= xy × x2y + xy × xy2 – xy × y3 + xy
= xy(x2y + xy2 – y3 + 1)
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३३]
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