Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122m, 22m, and 120m (see the given figure). The advertisements yield an earning of ₹ 5000 per m² per year. A company hired one of its walls for 3 months. How much rent did it pay?

Answer 1

The sides of the triangle (i.e., a, b, c) are 122 m, 22 m, and 120 m, respectively.

Perimeter of triangle = (122 + 22 + 120) m

2s = 264 m

s = 132 m

By Heron’s formula,

Area of triangle = `sqrt(s(s-a)(s-b)(s-c))`

Area of given triangle = `[sqrt(132(132-122)(132-22)(132-120))]m^2`

= `[sqrt(132(10)(110)(12))]m^2 = 1320m^2`

Rent of 1 m² area per year = ₹ 5000

Rent of 1 m² area per month = `₹ 5000/12`

Rent of 1320 m² area for 3 months

= `₹ (5000/12xx3xx1320)`

= ₹ (5000 × 330)

= ₹ 16,50,000

Therefore, the company had to pay ₹ 16,50,000.