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Question
The total energy of an electron in the first excited state of the hydrogen atom is about −3.4 eV.
What is the potential energy of the electron in this state?
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Solution
Potential energy (U) of the electron is equal to the negative of twice its kinetic energy.
⇒ U = −2 K
= − 2 × 3.4
= −6.8 eV
Hence, the potential energy of the electron in the given state is −6.8 eV.
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