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Question
The total energy of an electron in the first excited state of the hydrogen atom is about −3.4 eV.
What is the kinetic energy of the electron in this state?
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Solution
Total energy of the electron, E = −3.4 eV
Kinetic energy of the electron is equal to the negative of the total energy.
⇒ K = −E
= − (−3.4)
= +3.4 eV
Hence, the kinetic energy of the electron in the given state is +3.4 eV.
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