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Karnataka Board PUCPUC Science 2nd PUC Class 12

The total energy of an electron in the first excited state of the hydrogen atom is about −3.4 eV. What is the kinetic energy of the electron in this state? - Physics

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Question

The total energy of an electron in the first excited state of the hydrogen atom is about −3.4 eV.

What is the kinetic energy of the electron in this state?

Numerical
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Solution

Total energy of the electron, E = −3.4 eV

Kinetic energy of the electron is equal to the negative of the total energy.

⇒ K = −E

= − (−3.4)

= +3.4 eV

Hence, the kinetic energy of the electron in the given state is +3.4 eV.

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