Question

The system x – 2y = 3 and 3x + ky = 1 has a unique solution only when

Options

• k = –6

• k ≠ –6

• k = 0

• k ≠ 0

Answer 1

k ≠ –6

Explanation:

For a unique solution, we have `(a_1)/(a_2) ≠ (b_1)/(b_2)`.

So, `1/3 ≠ (-2)/k`

⇒ k ≠ –6