Question

The system kx – y = 2 and 6x – 2y = 3 has a unique solution only when

Options

• k = 0

• k ≠ 0

• k = 3

• k ≠ 3

Answer 1

k ≠ 3

Explanation:

For a unique solution, we have `(a_1)/(a_2) ≠ (b_1)/(b_2)`.

∴ `k/6 ≠ (-1)/(-2) `

⇒ k ≠ 3