Question

The system x + 2y = 3 and 5x + ky + 7 = 0 has no solution, when

Options

• k = 10

• k ≠ 10

• `k = (-7)/3`

• k = –21

Answer 1

k = 10

Explanation:

For no solution, we have `(a_1)/(a_2) = (b_1)/(b_2) ≠ (c_1)/(c_2)`.

∴ `1/5 = 2/k ≠ (-3)/7`

⇒ k = 10 and `k ≠ (-14)/3`.

Hence, k = 10.