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The sum of the radii of two circles is 7 cm, and the difference of their circumferences is 8 cm. Find the circumference of the circles. - Mathematics

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The sum of the radii of two circles is 7 cm, and the difference of their circumferences is 8 cm. Find the circumference of the circles.

The sum of radii of two circles is 7 cm and the difference of their circumference is 8 cm. Find the circumferences of the two circles.

Sum
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Solution

Let the radii of the two circles be r1 cm and r2 cm.

Now, Sum of the radii of the two circles = 7 cm

r1 + r2 = 7   ...(i)

Difference of the circumferences of the two circles = 88 cm

⇒ 2πr1 – 2πr2 = 8

⇒ 2π(r1 – r2) = 8

= `(r_1 - r_2) = 8/(2π)`

⇒ `r_1 - r_2 = (8)/(2 xx 22/7)`

⇒ `r_1 - r_2 = (8 xx 7)/44`

`r_1 - r_2 = 56/44`

`r_1 - r_2 = 14/11`   ...(ii)

Adding (i) and (ii), we get

`2r_1 = 91/11`

`r_1 = 91/22`

∴ Circumference of the first circle = 2πr1

= `2 xx 22/7 xx 91/22`

= 26 cm

Also,

`r_1 - r_2 = 14/11`

`91/22 - r^2 = 14/11` 

`91/22 - 14/11 = r_2`

`r_2 = 63/22`

∴ Circumference of the second circle = 2πr2

`= 2 xx 22/7 xx 63/22`

= 18 cm

Therefore, circumferences of the first and second circles are 18 cm and 26 cm, respectively.

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Chapter 18: Area of Circle, Sector and Segment - Exercise 18A [Page 831]

APPEARS IN

R.S. Aggarwal Mathematics [English] Class 10
Chapter 18 Area of Circle, Sector and Segment
Exercise 18A | Q 7 | Page 831
Nootan Mathematics [English] Class 9 ICSE
Chapter 16 Mensuration
Exercise 16C | Q 13. | Page 334
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