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Question
All the vertices of a rhombus lie on a circle. Find the area of the rhombus, if the area of the circle is 1256 cm2. (Use π = 3.14)
Sum
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Solution
Given that the area of the circle is 1256 cm2.
πr2 = 12563.14 × r2
3.14 × r2 = 1256
r2 = `1256/3.14`
r2 = 400
r = 20 cm
If all the vertices of a rhombus lie on a circle, then the rhombus is square.
Consider the following figure.

Here A, B, C and D are four points on the circle.
Thus, OA = OB = OC = OD = radius of the circle.
⇒ AC and BD are the diameters of the circle.
Consider the ΔADC.
By Pythagoras theorem, we have,
AD2 + CD2 = AC2
2AD2 = (2 × 20)2 ...[AD = CD]
2AD2 = (40)2
AD2 = `1600/2`
AD2 = 800 cm2
If AD is the side of the square, then AD2 is the area of the square.
Thus area of the square is 800 cm2.
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