Advertisements
Advertisements
Question
The speed of an express train is x km/hr arid the speed of an ordinary train is 12 km/hr less than that of the express train. If the ordinary train takes one hour longer than the express train to cover a distance of 240 km, find the speed of the express train.
Advertisements
Solution 1
Let the speed of express train is x
Km/hr. Speed of ordinary train is (x - 12) km/hr.
Time require to cover for each train is `(240)/x` and `(240)/(x - 12)` respectively.
According to question
`(240)/(x - 12) - (240)/x = 1`
`(240x - 240 (x - 12))/((x - 12) (x)) = 1`
240x - 240 (x - 12) = x (x - 12)
x2 - 12x - 2880 = 0
(x - 60) (x + 48) = 0
∴ x = 60 km/hr.
Speed of the express train is 60 km/hr.
Solution 2
Let the speed of express train = x km
Then speed of the ordinary train = (x – 12)km
Time is taken to cover 240km by the express
train = `(240)/x"hours"`
Time taken to cover 240km by the ordinary
train = `(240)/(x - 12)"hours"`
According to the condition,
`(240)/(x - 12) - (240)/x` = 1
⇒ `240[(1)/(x - 12) - (1)/x]` = 1
⇒ `240[(x - x + 12)/(x(x - 12))]` = 1
⇒ `240[(12)/(x^2 - 12x)]` = 1
⇒ 2880 = x2 - 12x
⇒ x2 - 12x - 2880 = 0
⇒ x2 - 60x + 48x - 2880 = 0
⇒ x(x - 60) + 48(x - 60) = 0
⇒ (x - 60)(x + 48) = 0
⇒ x = 60 or x = -48
⇒ x = 60 ...(Rejacting x = -48, as speed can't be negative)
Hence, speed of the express train = 60km/h.
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equations by factorization:
`(x+1)/(x-1)-(x-1)/(x+1)=5/6` , x ≠ 1, x ≠ -1
Find the value of k for which the following equations have real and equal roots:
\[x^2 + k\left( 2x + k - 1 \right) + 2 = 0\]
Write the sum of real roots of the equation x2 + |x| − 6 = 0.
If the equation x2 − ax + 1 = 0 has two distinct roots, then
If x = 1 is a common roots of the equations ax2 + ax + 3 = 0 and x2 + x + b = 0, then ab =
If \[\left( a^2 + b^2 \right) x^2 + 2\left( ab + bd \right)x + c^2 + d^2 = 0\] has no real roots, then
Two natural numbers differ by 4. If the sum of their square is 656, find the numbers.
The hypotenuse of a grassy land in the shape of a right triangle is 1 m more than twice the shortest side. If the third side is 7m more than the shortest side, find the sides of the grassy land.
Solve the following by reducing them to quadratic form:
`sqrt(y + 1) + sqrt(2y - 5) = 3, y ∈ "R".`
In each of the following, determine whether the given values are solution of the given equation or not:
`x = 1/x = (13)/(6), x = (5)/(6), x = (4)/(3)`
