Advertisements
Advertisements
प्रश्न
The speed of an express train is x km/hr arid the speed of an ordinary train is 12 km/hr less than that of the express train. If the ordinary train takes one hour longer than the express train to cover a distance of 240 km, find the speed of the express train.
Advertisements
उत्तर १
Let the speed of express train is x
Km/hr. Speed of ordinary train is (x - 12) km/hr.
Time require to cover for each train is `(240)/x` and `(240)/(x - 12)` respectively.
According to question
`(240)/(x - 12) - (240)/x = 1`
`(240x - 240 (x - 12))/((x - 12) (x)) = 1`
240x - 240 (x - 12) = x (x - 12)
x2 - 12x - 2880 = 0
(x - 60) (x + 48) = 0
∴ x = 60 km/hr.
Speed of the express train is 60 km/hr.
उत्तर २
Let the speed of express train = x km
Then speed of the ordinary train = (x – 12)km
Time is taken to cover 240km by the express
train = `(240)/x"hours"`
Time taken to cover 240km by the ordinary
train = `(240)/(x - 12)"hours"`
According to the condition,
`(240)/(x - 12) - (240)/x` = 1
⇒ `240[(1)/(x - 12) - (1)/x]` = 1
⇒ `240[(x - x + 12)/(x(x - 12))]` = 1
⇒ `240[(12)/(x^2 - 12x)]` = 1
⇒ 2880 = x2 - 12x
⇒ x2 - 12x - 2880 = 0
⇒ x2 - 60x + 48x - 2880 = 0
⇒ x(x - 60) + 48(x - 60) = 0
⇒ (x - 60)(x + 48) = 0
⇒ x = 60 or x = -48
⇒ x = 60 ...(Rejacting x = -48, as speed can't be negative)
Hence, speed of the express train = 60km/h.
APPEARS IN
संबंधित प्रश्न
The difference of two numbers is 4. If the difference of their reciprocals is 4/21. Find the numbers.
Determine two consecutive multiples of 3, whose product is 270.
The speed of a boat in still water is 8 km/hr. It can go 15 km upstream and 22 km downstream in 5 hours. Find the speed of the stream.
Solve the following quadratic equation by factorisation.
x2 + x – 20 = 0
Solve the following quadratic equation by factorisation.
m2 - 11 = 0
If `sqrt (2/3)` is a solution of equation 3x2 + mx + 2 = 0, find the value of m.
In each of the following determine whether the given values are solutions of the equation or not
2x2 - 6x + 3 = 0; x = `(1)/(2)`
In each of the following determine whether the given values are solutions of the equation or not.
9x2 - 3x - 2 = 0; x = `-(1)/(3), x = (2)/(3)`
Find the values of x if p + 1 =0 and x2 + px – 6 = 0
A dealer sells a toy for ₹ 24 and gains as much percent as the cost price of the toy. Find the cost price of the toy.
