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The slope of the line which is perpendicular to the line segment joining the points (8, −5) and (−4, 7) is ______.

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Question

The slope of the line which is perpendicular to the line segment joining the points (8, −5) and (−4, 7) is ______.

Options

  • −1

  • 1

  • 45°

  • −45°

MCQ
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Solution

The slope of the line which is perpendicular to the line segment joining the points (8, −5) and (−4, 7) is 1.

Explanation:

By formula,

Slope = `(y_2 − y_1)/(x_2 − x_1)`

Substituting values we get:

Slope of line passing through (8, −5) and (−4, 7)

= `(7−(−5))/(−4−8)`

= `(7+5)/(−12)`

= `12/(−12)`

= −1

Let slope of line perpendicular to line segment joining points (8, −5) and (−4, 7) be m.

We know that,

Product of slopes of two perpendicular lines = −1

∴ m × −1 = −1

⇒ m = `(−1)/(−1)` = 1

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Chapter 14: Equation of a Line - EXERCISE 14 (B) [Page 188]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 14 Equation of a Line
EXERCISE 14 (B) | Q 1. (e) | Page 188
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