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प्रश्न
The slope of the line which is perpendicular to the line segment joining the points (8, −5) and (−4, 7) is ______.
विकल्प
−1
1
45°
−45°
MCQ
रिक्त स्थान भरें
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उत्तर
The slope of the line which is perpendicular to the line segment joining the points (8, −5) and (−4, 7) is 1.
Explanation:
By formula,
Slope = `(y_2 − y_1)/(x_2 − x_1)`
Substituting values we get:
Slope of line passing through (8, −5) and (−4, 7)
= `(7−(−5))/(−4−8)`
= `(7+5)/(−12)`
= `12/(−12)`
= −1
Let slope of line perpendicular to line segment joining points (8, −5) and (−4, 7) be m.
We know that,
Product of slopes of two perpendicular lines = −1
∴ m × −1 = −1
⇒ m = `(−1)/(−1)` = 1
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