हिंदी

The slope of the line which is perpendicular to the line segment joining the points (8, −5) and (−4, 7) is ______.

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प्रश्न

The slope of the line which is perpendicular to the line segment joining the points (8, −5) and (−4, 7) is ______.

विकल्प

  • −1

  • 1

  • 45°

  • −45°

MCQ
रिक्त स्थान भरें
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उत्तर

The slope of the line which is perpendicular to the line segment joining the points (8, −5) and (−4, 7) is 1.

Explanation:

By formula,

Slope = `(y_2 − y_1)/(x_2 − x_1)`

Substituting values we get:

Slope of line passing through (8, −5) and (−4, 7)

= `(7−(−5))/(−4−8)`

= `(7+5)/(−12)`

= `12/(−12)`

= −1

Let slope of line perpendicular to line segment joining points (8, −5) and (−4, 7) be m.

We know that,

Product of slopes of two perpendicular lines = −1

∴ m × −1 = −1

⇒ m = `(−1)/(−1)` = 1

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Equation of a Line - EXERCISE 14 (B) [पृष्ठ १८८]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 14 Equation of a Line
EXERCISE 14 (B) | Q 1. (e) | पृष्ठ १८८
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