Advertisements
Advertisements
Question
The roots of the quadratic equation x2 – 6x – 7 = 0 are ______.
Options
–1 and 7
1 and 7
–1 or 7
1 and – 7
Advertisements
Solution
The roots of the quadratic equation x2 – 6x – 7 = 0 are –1 or 7.
Explanation:
Given quadratic equation be,
x2 – 6x – 7 = 0
`\implies` x2 – 7x + x – 7 = 0
`\implies` x(x – 7) + 1(x – 7) = 0
`\implies` (x – 7)(x + 1) = 0
Either x – 7 = 0 or x + 1 = 0
`\implies` x = 7 or x = – 1
`\implies` x = 7 or – 1
APPEARS IN
RELATED QUESTIONS
Find the value of k for which the roots are real and equal in the following equation:
3x2 − 5x + 2k = 0
Solve the following quadratic equation using formula method only :
x2 +10x- 8= 0
Find, using the quadratic formula, the roots of the following quadratic equations, if they exist
x2 + 4x + 5 = 0
Determine, if 3 is a root of the given equation
`sqrt(x^2 - 4x + 3) + sqrt(x^2 - 9) = sqrt(4x^2 - 14x + 16)`.
Find the value of k for which the given equation has real roots:
9x2 + 3kx + 4 = 0.
If `(2)/(3)` and – 3 are the roots of the equation px2+ 7x + q = 0, find the values of p and q.
If the roots of px2 + qx + 2 = 0 are reciprocal of each other, then:
If (x – a) is one of the factors of the polynomial ax2 + bx + c, then one of the roots of ax2 + bx + c = 0 is:
If (1 – p) is a root of the equation x2 + px + 1 – p = 0, then roots are:
The roots of the quadratic equation px2 – qx + r = 0 are real and equal if ______.
