Advertisements
Advertisements
Question
Solve the following quadratic equation using formula method only
`"x"^2 + 1/2 "x" = 3`
Advertisements
Solution
`"x"^2 + 1/2 "x" = 3`
2x2 + x = 6
2x2 + x - 6 = 0
a = 2 ; b = 1 ; c = -6
D = b2 - 4ac
= (1)2 - 4(2)(-6)
= 1 + 48
= 49
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(-1 +- sqrt 49)/4`
x = `(- 1 + 7)/4` , x = `(- 1 - 7)/4`
x = `6/4` , x = `-8/4`
x = `3/2` , x = - 2
APPEARS IN
RELATED QUESTIONS
Without solving, examine the nature of roots of the equation 4x2 – 4x + 1 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
(k + 1)x2 + 2(k + 3)x + (k + 8) = 0
Find the values of k for which the roots are real and equal in each of the following equation:
2x2 + kx + 3 = 0
Write the value of k for which the quadratic equation x2 − kx + 4 = 0 has equal roots.
`(2)/x^2 - (5)/x + 2` = 0
In each of the following determine the; value of k for which the given value is a solution of the equation:
x2 + 2ax - k = 0; x = - a.
α and β are the roots of 4x2 + 3x + 7 = 0, then the value of `1/α + 1/β` is:
Which of the following equations has two distinct real roots?
The sum of all integral values of k(k ≠ 0) for which the equation `2/(x - 1), 1/(x - 2) = 2/k` in x has no real roots, is ______.
Find the value of ‘c’ for which the quadratic equation
(c + 1) x2 - 6(c + 1) x + 3(c + 9) = 0; c ≠ - 1
has real and equal roots.
