Advertisements
Advertisements
Question
Advertisements
Solution
We know that, R = `"V"^2/"P"`
Thus, voltage remaining constant, resistance is inversely proportional to the power of the appliance; which means resistance of 60 W (220V) bulb is greater.
Hence, the given statement is false.
APPEARS IN
RELATED QUESTIONS
In 10 s, charge of 25 C leaves a battery, and 200 J of energy are delivered to an outside circuit a result.
What is the p.d. across the battery?
Which instrument is used to measure electric current? How should it be connected in a circuit?
Which unit could be used to measure current?
(a) Watt
(b) Coulomb
(c) Volt
(d) Ampere
A 720 W heater operates from a 220 V line voltage. Calculate:
(a) The electrical energy consumed by the heater in 3 h.
(b) The cost of electrical energy consumption at the rate of 60 paise per kWh.
Find the effective resistance in the following circuit diagrams (Fig.):

The circuit diagram (Fig.) shows a battery of e.m.f. 6 volts and internal
resistance of 0.8 Ω oonnected in series. Find the
(a) Current reoorded by the ammeter,
(b) P.d. across the terminals of the resistor B,
( c) Current passing through each of the resistors B, C and D, and
( d) P.d. across the terminals of the battery.

An electric bulb is marked '100 W, 250 V'. What information does this convey?
