Advertisements
Advertisements
Question
The population of a small locality was 4000 in 1979 and 4500 in 1981, By what percent had the population increase?
Advertisements
Solution
Year 1979 population = 4,000
Year 1981 population = 4,500
Increase in population = (4,500 – 4,000) = 500
percentage of increase in population = `500/4000xx100` = 12.5%
APPEARS IN
RELATED QUESTIONS
Express the following as decimal fractions:
\[\frac{1}{8} %\]
Gunpowder contains 75% nitre and 10% sulphur. Find the amount of the gunpowder which carries 9 kg nitre. What amount of gunpowder would contain 2.3 kg sulphur?
The number 8,000 is first increased by 20% and then decreased by 20%. Find the resulting number.
Express:
700 gm as a percentage of 2.8 kg.
In a school of 1400 students, there are 420 girls. The percentage of boys in the school is _______
Anbu scored 436 marks out of 500 in his exams. What was the percentage he scored?
A student earned a grade of 80% on a math test that had 20 problems. How many problems on this test did the student answer correctly?
What per cent of 1 km is 1000 metres?
Given below is a Mathematical term.

Find the percentage of consonants in the term.
Express 45 out of 100 as a percentage.
