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Question
The perpendicular bisector of side AB and bisector of angle ∠A of △ABC meet at point P. Then:
Options
PA = PB
PA = PC
PB = PC
PB bisects ∠ABC
MCQ
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Solution
PA = PB
Explanation:
We know that,
Locus of a point equidistant from two given points is the perpendicular bisector of the line joining the two points.
Since,
The perpendicular bisector of side AB and bisector of angle A of △ABC meet at point P.
∴ PA = PB.
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