Question

P is a point on bisector of angle A of △ABC. Then:

Options

• P is equidistant from the vertices B and C.

• PA = PC

• PA = PB

• P is equidistant from sides AB and AC.

Answer 1

P is equidistant from sides AB and AC.

Explanation:

We know that,

The locus of a point equidistant from two intersecting lines is the bisector of the angles between the lines.

Given,

P is a point on bisector of angle A of △ABC.

∴ P is equidistant from sides AB and AC of the △ABC.