Question

The perpendicular bisector of side AB and bisector of angle ∠A of  △ABC meet at point P. Then:

विकल्प

• PA = PB

• PA = PC

• PB = PC

• PB bisects ∠ABC

Answer 1

PA = PB

Explanation:

We know that,

Locus of a point equidistant from two given points is the perpendicular bisector of the line joining the two points.

Since,

The perpendicular bisector of side AB and bisector of angle A of △ABC meet at point P.

∴ PA = PB.