Advertisements
Advertisements
Question
The normal body temperature is 98.6°F. When Savitri was ill her temperature rose to 103.1°F. How many degrees above normal was that?
Advertisements
Solution
Given, normal body temperature = 98.6°F
And temperature rise to = 103.1°F
∴ Rise in temperature = (103.1 – 98.6)°F = 4.5°F
APPEARS IN
RELATED QUESTIONS
Subtract `1/6` from `1/2`.
Subtract `1 1/4` from `6 1/2`.
Solve:
`12/15 - 7/15`
Fill in the missing fraction.
`☐ - 3/21 = 5/21`
Solve:
`3/4 - 1/3`
Fill in the boxes:
`1/2 - ☐ = 1/6`
Heena’s father paid an electric bill of ₹ 385.70 out of a 500 rupee note. How much change should he have received?
When subtracting fractions that have the same denominator, which of the following steps is correct?
Using the method of separating whole numbers and fractions, how is the expression 3`2/5` − 2`1/7` rewritten?
Solve the subtraction: 3`1/2` − 1`1/4`
