Advertisements
Advertisements
प्रश्न
The normal body temperature is 98.6°F. When Savitri was ill her temperature rose to 103.1°F. How many degrees above normal was that?
Advertisements
उत्तर
Given, normal body temperature = 98.6°F
And temperature rise to = 103.1°F
∴ Rise in temperature = (103.1 – 98.6)°F = 4.5°F
APPEARS IN
संबंधित प्रश्न
Subtract:
`9/13 - 4/13`
Subtract:
`7/10 - 3/10`
`7/10` of a wall is to be painted. Ramu has painted `4/10` of it. How much more needs to be painted?
From his office, a person wants to reach his house on foot which is at a distance of `5 3/4` km. If he had walked `2 1/2` km, how much distance still he has to walk to reach his house?
The sum of two fractions is `5 3/9`. If one of the fractions is `2 3/4`, find the other fraction
Subtract the following.
`8/15 - 2/15`
Subtract `1 1/4` from `6 1/2`.
Solve:
`7/7 - 5/7`
Solve:
`1 - 2/3 (1 = 3/3)`
Solve:
`16/5 - 7/5`
