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The Molar Conductivity of 0.05 M Bacl2 Solution at 25° C is 223ω-1 Cm2 Mol-1 . What is Its Conductivity?

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Question

The molar conductivity of 0.05 M BaCl2 solution at 25° C is 223Ω-1 cm2 mol-1. What is its conductivity?

Answer in Brief
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Solution

C = 0.05 M
λm = 223Ω-1  cm2 mol-1

λm = `(1000"k")/"C"`

`therefore  "k" = (λ_"m" xx "C")/1000`

`= (223 xx 0.05)/1000`

= 0.01115 S cm-1

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2018-2019 (March) Set 1

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