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Question
0.05 M NaOH solution offered a resistance of 31.6 Ω in a conductivity cell at 298 K. If the cell constant of the cell is 0.367 cm-1, calculate the molar conductivity of NaOH solution.
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Solution
Given:
Cell constant (b) = 0.367 cm–1
Molar concentration (C) = 0.05 M NaOH
Resistance (R) = 31.6 Ω
To find: Molar conductivity (^)
Solution:
∧m(NaOH) = ?
`k_((NaOH)) = b/R_((NaOH)) = 0.01161 Ω^-1 cm^-1`
`∧_(m(NaOH)) = (k xx 1000)/C`
`= (0.01161 xx 1000)/0.05`
= 232.2 Ω-1 cm2 mol-1
Molar conductivity = ∧m = 232.2 Ω-1 cm2 mol-1
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