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Question
The resistance of a conductivity cell with cell constant 1.14 cm−1, containing 0.001 M KCl at 298 K is 1500 Ω. The molar conductivity of 0.001 MKCl solution at 298 K in S cm2 mol−1 is ______. (Integer answer)
Options
86
860
920
760
MCQ
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Solution
The resistance of a conductivity cell with cell constant 1.14 cm−1, containing 0.001 M KCl at 298 K is 1500 Ω. The molar conductivity of 0.001 MKCl solution at 298 K in S cm2 mol−1 is 760.
Explanation:
`K = 1/R xx l/A`
`((1/1500) xx 1.14) S cm^-1`
`=>` ∧m = `1000 xx ((1.14/1500))/(0.001)` S cm2 mol−1
= 760 S cm2 mol−1
⇒ 760
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