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Question
The maximum value of the objective function Z = 3x + 5y subject to the constraints x ≥ 0, y ≥ 0 and 2x + 5y ≤ 10 is:
Options
6
15
25
31
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Solution
15
Explanation:
2x + 5y = 10
| x | 0 | 5 |
| y | 2 | 0 |
| Corner points | Z = 3x + 5y |
| O(0, 0) | 0 |
| A(5, 0) | 15 |
| B(0, 2) | 12 |
∴ Maximum value is 15
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