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Question
The minimum value of the objective function Z = x + 3y subject to the constraints 2x + y ≤ 20, x + 2y ≤ 20, x > 0 and y > 0 is
Options
10
20
0
5
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Solution
0
Explanation:
2x + y = 20
| x | 0 | 10 |
| y | 20 | 0 |
x + y = 20
| x | 0 | 20 |
| y | 20 | 0 |
| Corner points | Z = x + 3y |
| O(0, 0) | 0 |
| A(0, 20) | 60 |
| B(10, 0) | 10 |
| C(20, 0) | 20 |
∴ Minimum value is 0
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