Question

The maximum value of the objective function Z = 3x + 5y subject to the constraints x ≥ 0, y ≥ 0 and 2x + 5y ≤ 10 is:

पर्याय

• 6

• 15

• 25

• 31

Answer 1

15

Explanation:

2x + 5y = 10

x	0	5
y	2	0

Corner points	Z = 3x + 5y
O(0, 0)	0
A(5, 0)	15
B(0, 2)	12

∴ Maximum value is 15