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The line segment joining (\mathrm{A}(–7, 2)) and (\mathrm{B}(3, –8)) is divided by the x-axis in the ratio:

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Question

The line segment joining \(\mathrm{A}(-7, 2)\) and \(\mathrm{B}(3, -8)\) is divided by the x-axis in the ratio: 

Options

  • 1 : 4

  • 3 : 7

  • 4 : 1

  • 7 : 3

MCQ
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Solution

1 : 4

Explanation:

Let the ratio be \(k : 1\); the point of division has y-coordinate 0:

$$\frac{k(-8) + 1(2)}{k + 1} = 0$$

$$\Rightarrow 2 - 8k = 0$$

$$\Rightarrow k = \frac{1}{4}$$

Hence the ratio is 1 : 4.

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Chapter 13: Section and Mid-point Formulae - COMPETENCY-FOCUSED QUESTIONS [Page 212]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 13 Section and Mid-point Formulae
COMPETENCY-FOCUSED QUESTIONS | Q 8. | Page 212
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