Advertisements
Advertisements
Question
The hypotenuse of a right-angled triangle is 17cm. If the smaller side is multiplied by 5 and the larger side is doubled, the new hypotenuse will be 50 cm. Find the length of each side of the triangle.
Advertisements
Solution
Let hypotenuse=h, and other sides by x and y (x bigger than y). As per the question,
h = 17 , X2 + y2 = 17 X 17
⇒ x2 + y2 = 289 ..... (i)
In second scenario, sides become Sy and 2x, new h becomes 50 cm
⇒ (5y)2 + (2x)2 = 50 x 50
⇒ 25y2 + 4x2= 2500
⇒ (21y2 + 4 y2 )+ 4x2 = 2500 ..... (ii)
Putitng (i) in (ii), we get:
21y2 + 4(289) = 2500
⇒ 21y2= 1344
⇒ y2 = 64
Hence y = 8cm.
Putting this is (i), we get
⇒ x2= 289 - 64 = 225
⇒ x= 25cm
Hence, the sides are 8, 15, 17 cm.
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equation by factorization method : `3x^2-29x+40=0`
Divide 29 into two parts so that the sum of the squares of the parts is 425.
The sum of two number a and b is 15, and the sum of their reciprocals `1/a` and `1/b` is 3/10. Find the numbers a and b.
The difference of squares of two numbers is 180. The square of the smaller number is 8 times the larger number. Find two numbers.
Solve:
x(x + 1) + (x + 2)(x + 3) = 42
Solve the following quadratic equations by factorization: \[\frac{3}{x + 1} + \frac{4}{x - 1} = \frac{29}{4x - 1}; x \neq 1, - 1, \frac{1}{4}\]
Two natural numbers differ by 4. If the sum of their square is 656, find the numbers.
Solve the following equation by factorization
x (2x + 1) = 6
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
The hotel bill for a number of people for an overnight stay is Rs. 4800. If there were 4 more, the bill each person had to pay would have reduced by Rs. 200. Find the number of people staying overnight.
