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The Product of a Girl'S Age Five Years Ago and Her Age 3 Years Later is 105. Find Her Present Age.

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Question

The product of a girl's age five years ago and her age 3 years later is 105. Find her present age.

Sum
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Solution

Let the present age of the Girl be G year. Then, as per the question description, 

(G - S)(G + 3) = 105 

⇒ G2 - 2G - 120 = 0 

⇒  G2 -12G + 10G - 120 = 0 

⇒  G (G - 12) +10 (G - 12) = 0  

⇒  G=12 , G = -10 (Agecannotbe negative) 

⇒  G=12 Years 

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Chapter 6: Problems Based On Quadratic Equations - Exercise 7.1

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Frank Mathematics Part 2 [English] Class 10 ICSE
Chapter 6 Problems Based On Quadratic Equations
Exercise 7.1 | Q 21

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