Advertisements
Advertisements
प्रश्न
The hypotenuse of a right-angled triangle is 17cm. If the smaller side is multiplied by 5 and the larger side is doubled, the new hypotenuse will be 50 cm. Find the length of each side of the triangle.
Advertisements
उत्तर
Let hypotenuse=h, and other sides by x and y (x bigger than y). As per the question,
h = 17 , X2 + y2 = 17 X 17
⇒ x2 + y2 = 289 ..... (i)
In second scenario, sides become Sy and 2x, new h becomes 50 cm
⇒ (5y)2 + (2x)2 = 50 x 50
⇒ 25y2 + 4x2= 2500
⇒ (21y2 + 4 y2 )+ 4x2 = 2500 ..... (ii)
Putitng (i) in (ii), we get:
21y2 + 4(289) = 2500
⇒ 21y2= 1344
⇒ y2 = 64
Hence y = 8cm.
Putting this is (i), we get
⇒ x2= 289 - 64 = 225
⇒ x= 25cm
Hence, the sides are 8, 15, 17 cm.
APPEARS IN
संबंधित प्रश्न
Solve each of the following equations by factorization:
`x+1/x=2.5`
Find the two consecutive positive even integers whose product is 288.
Solve for x: `3x^2-2sqrt3x+2=0`
Find the value of p for which the quadratic equation
\[\left( p + 1 \right) x^2 - 6(p + 1)x + 3(p + 9) = 0, p \neq - 1\] has equal roots. Hence, find the roots of the equation.
Disclaimer: There is a misprinting in the given question. In the question 'q' is printed instead of 9.
If 2 is a root of the equation x2 + bx + 12 = 0 and the equation x2 + bx + q = 0 has equal roots, then q =
Solve the following equation :
`1/(("x" - 1)(x - 2)) + 1/(("x" - 2)("x" - 3)) + 1/(("x" - 3)("x" -4)) = 1/6`
Solve the following equation by factorization
(x – 3) (2x + 5) = 0
Solve the following equation by factorization
`(2)/(3)x^2 - (1)/(3)x` = 1
Solve the following equation by factorization
5x2 – 8x – 4 = 0 when x∈Q
Solve the following quadratic equation by factorisation method:
x2 + x – 20 = 0
