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The following is the distribution of 160 Workers according to the wages in a certain factory: Wages more than (in ₹) No. of workers 8000 160 9000 155 10000 137 11000 91 12000 57 13000 23 14000 10

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Question

The following is the distribution of 160 Workers according to the wages in a certain factory:

Wages more than
(in ₹)
No. of workers
8000 160
9000 155
10000 137
11000 91
12000 57
13000 23
14000 10
15000 1
16000 0

Determine the values of all quartiles and interpret the results.

Sum
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Solution

The given table is a more than cumulative frequency. We transform the given table into less than cumulative frequency.

We construct the less than cumulative frequency table as given below:

Wages
(in ₹)
No. of workers (f) Less than Cumulative frequency
(c.f.)
8000 – 9000 160 – 155 = 5 5
9000 – 10000 155 –  137 = 18 23
10000 – 11000 137 –  91 = 46 69 ← Q1
11000 – 12000 91 –  57 = 34 103 ← Q2
12000 – 13000 57 –  23 = 34 137 ← Q3
13000 – 14000 23 –  10 = 13 150
14000 – 15000 10 –  1 = 9 159
15000 – 16000 1 –  0 = 1 160
16000 – 17000 0 160
Total 160  

Here, N = 160
∴ Q1 class = class containing `("N"/4)^"th"` observation

∴ `"N"/4=160/4` = 40

Cumulative frequency which is just greater than (or equal to) 40 is 69.

∴ Q1 lies in the class 10000 – 11000
∴ L = 10000, f = 46, c.f. = 23, h = 1000

Q1 = `"L"+"h"/"f"("N"/4-"c.f.")`

= `10000 + (1000)/(46)(40 - 23)`

= `10000+1000/46(17)`

= `10000+17000/46`

= 10000 + 369.57
= 10369.57
Q2 class = class containing `((2"N")/4)^"th"` observation

∴ `(2"N")/4=(2xx160)/4` = 80

Cumulative frequency which is just greater than (or equal to) 80 is 103
∴ Q2 lies in the class 11000 – 12000
∴ L = 11000, f = 34, c.f. = 69, h = 1000

Q2 = `"L"+"h"/"f"("2N"/4 - "c.f.")`

= `11000 + (1000)/(34)(80 - 69)`

= `11000+1000/34(11)`

= `11000+11000/34`

=  11000 + 323.529
= 11323.529

Q3 class = class containing `(("3N")/4)^"th"` observation

`(3"N")/(4) = (3(160))/(4)` = 120

Cumulative frequency which is just greater than (or equal to) 120 is 137.
∴ Q3 lies in the class 12000 – 13000
∴ L = 12000, f = 34, c.f. = 103; h = 1000

Q3 = `"L"+"h"/"f"((3"N")/4 - "c.f.")`

= `12000 + (1000)/(34)(120 - 103)`

= `12000+1000/34(17)`

= `12000+1000/2`

= 12000 + 500
= 12500
∴ The quartiles are
Q1 =  Rs.10369.57
Q2 = Rs. 11323.529
Q3 = Rs. 12500
Q1 < Q2 < Q3.

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Chapter 1: Partition Values - Exercise 1.1 [Page 8]
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