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प्रश्न
The following is the distribution of 160 Workers according to the wages in a certain factory:
| Wages more than (in ₹) |
No. of workers |
| 8000 | 160 |
| 9000 | 155 |
| 10000 | 137 |
| 11000 | 91 |
| 12000 | 57 |
| 13000 | 23 |
| 14000 | 10 |
| 15000 | 1 |
| 16000 | 0 |
Determine the values of all quartiles and interpret the results.
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उत्तर
The given table is a more than cumulative frequency. We transform the given table into less than cumulative frequency.
We construct the less than cumulative frequency table as given below:
| Wages (in ₹) |
No. of workers (f) | Less than Cumulative frequency (c.f.) |
| 8000 – 9000 | 160 – 155 = 5 | 5 |
| 9000 – 10000 | 155 – 137 = 18 | 23 |
| 10000 – 11000 | 137 – 91 = 46 | 69 ← Q1 |
| 11000 – 12000 | 91 – 57 = 34 | 103 ← Q2 |
| 12000 – 13000 | 57 – 23 = 34 | 137 ← Q3 |
| 13000 – 14000 | 23 – 10 = 13 | 150 |
| 14000 – 15000 | 10 – 1 = 9 | 159 |
| 15000 – 16000 | 1 – 0 = 1 | 160 |
| 16000 – 17000 | 0 | 160 |
| Total | 160 |
Here, N = 160
∴ Q1 class = class containing `("N"/4)^"th"` observation
∴ `"N"/4=160/4` = 40
Cumulative frequency which is just greater than (or equal to) 40 is 69.
∴ Q1 lies in the class 10000 – 11000
∴ L = 10000, f = 46, c.f. = 23, h = 1000
Q1 = `"L"+"h"/"f"("N"/4-"c.f.")`
= `10000 + (1000)/(46)(40 - 23)`
= `10000+1000/46(17)`
= `10000+17000/46`
= 10000 + 369.57
= 10369.57
Q2 class = class containing `((2"N")/4)^"th"` observation
∴ `(2"N")/4=(2xx160)/4` = 80
Cumulative frequency which is just greater than (or equal to) 80 is 103
∴ Q2 lies in the class 11000 – 12000
∴ L = 11000, f = 34, c.f. = 69, h = 1000
Q2 = `"L"+"h"/"f"("2N"/4 - "c.f.")`
= `11000 + (1000)/(34)(80 - 69)`
= `11000+1000/34(11)`
= `11000+11000/34`
= 11000 + 323.529
= 11323.529
Q3 class = class containing `(("3N")/4)^"th"` observation
`(3"N")/(4) = (3(160))/(4)` = 120
Cumulative frequency which is just greater than (or equal to) 120 is 137.
∴ Q3 lies in the class 12000 – 13000
∴ L = 12000, f = 34, c.f. = 103; h = 1000
Q3 = `"L"+"h"/"f"((3"N")/4 - "c.f.")`
= `12000 + (1000)/(34)(120 - 103)`
= `12000+1000/34(17)`
= `12000+1000/2`
= 12000 + 500
= 12500
∴ The quartiles are
Q1 = Rs.10369.57
Q2 = Rs. 11323.529
Q3 = Rs. 12500
Q1 < Q2 < Q3.
