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Following is the grouped data for duration of fixed deposits of 100 senior citizens from a certain bank: Fixed deposit (in days) 0 – 180 180 – 360 360 – 540 540 – 720 720 – 900 No. of senior citizens - Mathematics and Statistics

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Question

Following is the grouped data for duration of fixed deposits of 100 senior citizens from a certain bank:

Fixed deposit (in days) 0 – 180 180 – 360 360 – 540 540 – 720 720 – 900
No. of senior citizens 15 20 25 30 10

Calculate the limits of fixed deposits of central 50% senior citizens.

Sum
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Solution

We construct the less than cumulative frequency table as given below:

Fixed deposit (in days) No. of senior citizens
(f)
Less than Cumulative frequency
(c.f.)
0 – 180 15 15
180 – 360 20 35 ← Q1
360 – 540 25 60
540 – 720 30 90 ← Q3
720 – 900 10 100
Total 100  

To find the limits of fixed deposits of central 50% senior citizens, we have to find Q1 and Q3.

Here, N = 100

Q1 class = class containing `(("N")/4)^"th"` observation

∴ `"N"/4=100/4` = 25

Cumulative frequency which is just greater than (or equal to) 25 is 35.

∴ Q1 lies in the class 180 – 360.
∴  L= 180, f = 20, c.f. = 15, h = 180

∴ Q1 = `"L"+"h"/"f"("N"/4 - "c.f.")`

= `180 + (180)/(20)(25 - 15)`

= 180 + 9(10)
= 180 + 90
∴ Q1 = 270

Q3 class = class containing `(("3N")/4)^"th"` observation

∴ `(3"N")/(4) = (3(100))/(4)` = 75

Cumulative frequency which is just greater than (or equal to) 75 is 90.
∴ Q3 lies in the class 540 – 720
∴ L= 540, f = 30, c.f. = 60, h = 180

∴ Q3 = `"L"+"h"/"f"("3N"/4 - "c.f.")`

= `540 + (180)/(30)(75 - 60)`

 = 540 + 6(15)
= 540 + 90
∴ Q3 = 630
∴ Limits of the duration of fixed deposits of central 50% of senior citizens are from 270 to 630.

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Chapter 1: Partition Values - Exercise 1.1 [Page 8]
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