English
Karnataka Board PUCPUC Science Class 11

The Energy of a Photon of a Characteristic X-ray from a Coolidge Tube Comes from - Physics

Advertisements
Advertisements

Question

The energy of a photon of a characteristic X-ray from a Coolidge tube comes from

Options

  •  the kinetic energy of the striking electron

  •  the kinetic energy of the free electrons of the target

  • the kinetic energy of the ions of the target

  • an atomic transition in the target

MCQ
Advertisements

Solution

an atomic transition in the target

In an X-ray tube, electrons are emitted by the filament. These electrons are made to strike the filament by applying an electric field between the filament and the target. As a result of it, the kinetic energy of the electrons is lost to the target atoms. This energy is utilised by the target atoms to knock out an electron from the innermost shell. Consequently, the electron makes a transition from the higher energy state to this vacant shell. Due to this transition, the difference of energy of the two states gives photon of characteristic X-ray.

shaalaa.com
  Is there an error in this question or solution?
Chapter 22: X-rays - MCQ [Page 393]

APPEARS IN

RELATED QUESTIONS

What role dose infra-red radiation play in physical therapy?


Name the electromagnetic radiations used for (a) water purification, and (b) eye surgery.


Why are infra-red waves often called heat waves? Explain.


What do you understand by the invisible spectrum? 


Which part of electromagnetic spectrum is used in radar systems?


Consider a photon of a continuous X-ray coming from a Coolidge tube. Its energy comes from


Frequencies of Kα X-rays of different materials are measured. Which one of the graphs in the figure may represent the relation between the frequency v and the atomic number ?


Mark the correct options.
(a) An atom with a vacancy has smaller energy that a neutral atom.
(b) K X-ray is emitted when a hole makes a jump from the K shell to some other shell.
(c) The wavelength of K X-ray is smaller than the wavelength of L X-ray of the same material.
(d) The wavelength of Kα X-ray is smaller than the wavelength of Kβ X-ray of the same material.


For a given material, the energy and wavelength of characteristic X-rays satisfy
(a) E(Kα) > E(Kβ) > E(Kγ)
(b) E(Mα) > E(Lα) > E(Kα)
(c) λ(Kα) > λ(Kβ) > λ(Kγ)
(d) λ(Mα) > λ(Lα) > λ(Kα).


The potential difference applied to an X-ray tube is increased. As a result, in the emitted radiation,
(a) the intensity increases
(b) the minimum wavelength increases
(c) the intensity remains unchanged
(d) the minimum wavelength decreases.


The energy of a silver atom with a vacancy in K shell is 25.31 keV, in L shell is 3.56 keV and in M shell is 0.530 keV higher than the energy of the atom with no vacancy. Find the frequency of Kα, Kβ and Lα X-rays of silver.

(Use Planck constant h = 6.63 × 10-34 Js= 4.14 × 10-15 eVs, speed of light c = 3 × 108 m/s.)


Give one use of electromagnetic radiation in Microwaves.


Give one use of electromagnetic radiations in Infrared radiation.


Answer briefly.

Does an ordinary electric lamp emit EM waves?


An e.m. wave exerts pressure on the surface on which it is incident. Justify.


Light of wavelength `3500A` is incident on two metals A and B whose work functions are 3.2 eV and 1.9 eV respectively. Which metal will emit photoelectrons?


Radio waves of constant amplitude can be generated with.


One requires 11eV of energy to dissociate a carbon monoxide molecule into carbon and oxygen atoms. The minimum frequency of the appropriate electromagnetic radiation to achieve the dissociation lies in ______.


Given below in the left column are different modes of communication using the kinds of waves given in the right column. 

A.  Optical Fibre
Communication
P. Ultrasound
B. Radar Q. Infrared Light
C. Sonar R. Microwaves
D. Mobile Phones  S. Radio Waves

From the options given below, find the most appropriate match between entries in the left and the right column.


Which is the correct ascending order of wavelengths?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×