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Karnataka Board PUCPUC Science Class 11

The Electron Beam in a Colour Tv is Accelerated Through 32 Kv and Then Strikes the Screen. What is the Wavelength of the Most Energetic X-ray Photon?

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Question

The electron beam in a colour TV is accelerated through 32 kV and then strikes the screen. What is the wavelength of the most energetic X-ray photon?

(Use Planck constant h = 6.63 × 10-34 Js= 4.14 × 10-15 eVs, speed of light c = 3 × 108 m/s.)

Sum
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Solution

Given:-

Potential of the electron beam, V = 32 kV = 32 × 103 V

`"Energy", E = 32 xx 10^3  "eV"`

Wavelength of the X-ray photon (`lambda`) is given by

`lambda = (hc)/E`

Here,
h = Planck's constant
c = Speed of light

`therefore lambda = (hc)/E`

`⇒ lambda = (1242  "eVnm")/(32 xx 10^3)`

`⇒ lambda = 38.8 xx 10^-3  "nm"`

`⇒ lambda = 38.8  "pm"`

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Chapter 44: X-rays - Exercises [Page 395]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 44 X-rays
Exercises | Q 9 | Page 395

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