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Question
The distance of the point (–6, 8) from x-axis is ______.
Options
6 units
– 6 units
8 units
10 units
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Solution
The distance of the point (–6, 8) from x-axis is 8 units.
Explanation:
The distance of the point (x, y) from x-axis is y-coordinate
∴ The distance of the point (–6, 8) from x-axis is 8 units.

RELATED QUESTIONS
Prove that the points (3, -2), (4, 0), (6, -3) and (5, -5) are the vertices of a parallelogram.
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joining (3, -1) and (8, 9).
The line joining the points (2, 1) and (5, −8) is trisected at the points P and Q. If point P lies on the line 2x − y + k = 0. Find the value of k.
If A(−3, 5), B(−2, −7), C(1, −8) and D(6, 3) are the vertices of a quadrilateral ABCD, find its area.
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If point P is midpoint of segment joining point A(– 4, 2) and point B(6, 2), then the coordinates of P are ______
The perpendicular distance of the point P(3, 4) from the y-axis is ______.
Find the coordinates of the point which lies on x and y axes both.
Assertion (A): The ratio in which the line segment joining (2, -3) and (5, 6) internally divided by x-axis is 1:2.
Reason (R): as formula for the internal division is `((mx_2 + nx_1)/(m + n) , (my_2 + ny_1)/(m + n))`
Assertion (A): Mid-point of a line segment divides the line segment in the ratio 1 : 1
Reason (R): The ratio in which the point (−3, k) divides the line segment joining the points (− 5, 4) and (− 2, 3) is 1 : 2.
